3.381 \(\int c^5 x^5 (\frac {a}{x^4}+b x^n)^{3/2} \, dx\)

Optimal. Leaf size=100 \[ -\frac {2 a^{3/2} c^5 \tanh ^{-1}\left (\frac {\sqrt {a}}{x^2 \sqrt {\frac {a}{x^4}+b x^n}}\right )}{n+4}+\frac {2 c^5 x^6 \left (\frac {a}{x^4}+b x^n\right )^{3/2}}{3 (n+4)}+\frac {2 a c^5 x^2 \sqrt {\frac {a}{x^4}+b x^n}}{n+4} \]

[Out]

2/3*c^5*x^6*(a/x^4+b*x^n)^(3/2)/(4+n)-2*a^(3/2)*c^5*arctanh(a^(1/2)/x^2/(a/x^4+b*x^n)^(1/2))/(4+n)+2*a*c^5*x^2
*(a/x^4+b*x^n)^(1/2)/(4+n)

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Rubi [A]  time = 0.21, antiderivative size = 100, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {12, 2028, 2029, 206} \[ -\frac {2 a^{3/2} c^5 \tanh ^{-1}\left (\frac {\sqrt {a}}{x^2 \sqrt {\frac {a}{x^4}+b x^n}}\right )}{n+4}+\frac {2 c^5 x^6 \left (\frac {a}{x^4}+b x^n\right )^{3/2}}{3 (n+4)}+\frac {2 a c^5 x^2 \sqrt {\frac {a}{x^4}+b x^n}}{n+4} \]

Antiderivative was successfully verified.

[In]

Int[c^5*x^5*(a/x^4 + b*x^n)^(3/2),x]

[Out]

(2*a*c^5*x^2*Sqrt[a/x^4 + b*x^n])/(4 + n) + (2*c^5*x^6*(a/x^4 + b*x^n)^(3/2))/(3*(4 + n)) - (2*a^(3/2)*c^5*Arc
Tanh[Sqrt[a]/(x^2*Sqrt[a/x^4 + b*x^n])])/(4 + n)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 2028

Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a*x^j + b
*x^n)^p)/(c*p*(n - j)), x] + Dist[a/c^j, Int[(c*x)^(m + j)*(a*x^j + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b, c,
j, m, n}, x] && IGtQ[p + 1/2, 0] && NeQ[n, j] && EqQ[Simplify[m + j*p + 1], 0] && (IntegerQ[j] || GtQ[c, 0])

Rule 2029

Int[(x_)^(m_.)/Sqrt[(a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.)], x_Symbol] :> Dist[-2/(n - j), Subst[Int[1/(1 - a*x^2
), x], x, x^(j/2)/Sqrt[a*x^j + b*x^n]], x] /; FreeQ[{a, b, j, n}, x] && EqQ[m, j/2 - 1] && NeQ[n, j]

Rubi steps

\begin {align*} \int c^5 x^5 \left (\frac {a}{x^4}+b x^n\right )^{3/2} \, dx &=c^5 \int x^5 \left (\frac {a}{x^4}+b x^n\right )^{3/2} \, dx\\ &=\frac {2 c^5 x^6 \left (\frac {a}{x^4}+b x^n\right )^{3/2}}{3 (4+n)}+\left (a c^5\right ) \int x \sqrt {\frac {a}{x^4}+b x^n} \, dx\\ &=\frac {2 a c^5 x^2 \sqrt {\frac {a}{x^4}+b x^n}}{4+n}+\frac {2 c^5 x^6 \left (\frac {a}{x^4}+b x^n\right )^{3/2}}{3 (4+n)}+\left (a^2 c^5\right ) \int \frac {1}{x^3 \sqrt {\frac {a}{x^4}+b x^n}} \, dx\\ &=\frac {2 a c^5 x^2 \sqrt {\frac {a}{x^4}+b x^n}}{4+n}+\frac {2 c^5 x^6 \left (\frac {a}{x^4}+b x^n\right )^{3/2}}{3 (4+n)}-\frac {\left (2 a^2 c^5\right ) \operatorname {Subst}\left (\int \frac {1}{1-a x^2} \, dx,x,\frac {1}{x^2 \sqrt {\frac {a}{x^4}+b x^n}}\right )}{4+n}\\ &=\frac {2 a c^5 x^2 \sqrt {\frac {a}{x^4}+b x^n}}{4+n}+\frac {2 c^5 x^6 \left (\frac {a}{x^4}+b x^n\right )^{3/2}}{3 (4+n)}-\frac {2 a^{3/2} c^5 \tanh ^{-1}\left (\frac {\sqrt {a}}{x^2 \sqrt {\frac {a}{x^4}+b x^n}}\right )}{4+n}\\ \end {align*}

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Mathematica [A]  time = 0.08, size = 96, normalized size = 0.96 \[ \frac {2 c^5 x^2 \sqrt {\frac {a}{x^4}+b x^n} \left (\sqrt {a+b x^{n+4}} \left (4 a+b x^{n+4}\right )-3 a^{3/2} \tanh ^{-1}\left (\frac {\sqrt {a+b x^{n+4}}}{\sqrt {a}}\right )\right )}{3 (n+4) \sqrt {a+b x^{n+4}}} \]

Antiderivative was successfully verified.

[In]

Integrate[c^5*x^5*(a/x^4 + b*x^n)^(3/2),x]

[Out]

(2*c^5*x^2*Sqrt[a/x^4 + b*x^n]*(Sqrt[a + b*x^(4 + n)]*(4*a + b*x^(4 + n)) - 3*a^(3/2)*ArcTanh[Sqrt[a + b*x^(4
+ n)]/Sqrt[a]]))/(3*(4 + n)*Sqrt[a + b*x^(4 + n)])

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(c^5*x^5*(a/x^4+b*x^n)^(3/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b x^{n} + \frac {a}{x^{4}}\right )}^{\frac {3}{2}} c^{5} x^{5}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(c^5*x^5*(a/x^4+b*x^n)^(3/2),x, algorithm="giac")

[Out]

integrate((b*x^n + a/x^4)^(3/2)*c^5*x^5, x)

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maple [F]  time = 0.73, size = 0, normalized size = 0.00 \[ \int \left (b \,x^{n}+\frac {a}{x^{4}}\right )^{\frac {3}{2}} c^{5} x^{5}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(c^5*x^5*(a/x^4+b*x^n)^(3/2),x)

[Out]

int(c^5*x^5*(a/x^4+b*x^n)^(3/2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ c^{5} \int {\left (b x^{n} + \frac {a}{x^{4}}\right )}^{\frac {3}{2}} x^{5}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(c^5*x^5*(a/x^4+b*x^n)^(3/2),x, algorithm="maxima")

[Out]

c^5*integrate((b*x^n + a/x^4)^(3/2)*x^5, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int c^5\,x^5\,{\left (b\,x^n+\frac {a}{x^4}\right )}^{3/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(c^5*x^5*(b*x^n + a/x^4)^(3/2),x)

[Out]

int(c^5*x^5*(b*x^n + a/x^4)^(3/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ c^{5} \left (\int a x \sqrt {\frac {a}{x^{4}} + b x^{n}}\, dx + \int b x^{5} x^{n} \sqrt {\frac {a}{x^{4}} + b x^{n}}\, dx\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(c**5*x**5*(a/x**4+b*x**n)**(3/2),x)

[Out]

c**5*(Integral(a*x*sqrt(a/x**4 + b*x**n), x) + Integral(b*x**5*x**n*sqrt(a/x**4 + b*x**n), x))

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